Report: Wisconsin is home to 12 of the nation's top 20 drunkest cities

24/7 Wall Street has released its annual ranking of the nation's drunkest cities, and Wisconsin is home to 12 of the top 20 cities.

According to the report, the following 20 cities are the drunkest cities in the U.S.:

1. Appleton, Wis.
2. Oshkosh/Neenah, Wis.
3. Green Bay, Wis.
4. Madison, Wis.
5. Fargo, N.D.
6. La Crosse/Onalaska, Wis.
7. Fond du Lac, Wis.
8. Ames, Iowa
9. Eau Claire, Wis.
10. Mankato/North Mankato, Minn.
11. Wausau, Wis.
12. Sheboygan, Wis.
13. Missoula, Mont.
14. Grand Forks, N.D.
15. Racine, Wis.
16. Janesville/Beloit, Wis.
17. Milwaukee/Waukesha/West Allis, Wis.
18. Lincoln, Neb.
19. Iowa City, Iowa
20. Corvallis, Ore.

The report looked at the percentage of adults drinking excessively, percentage of driving deaths involving alcohol, number of premature deaths and the median household income.

In the 2018 report, 10 Wisconsin cities were on the list.

• Lawmakers Drafting Legislation To Close Drunk Driving Loophole

Excessive alcohol use kills nearly 88,000 people per year, according to the Centers for Disease Control and Prevention. For women, the CDC defines excessive drinking as having four or more drinks during a single occasion, and for men as having five or more drinks. Nationwide, 18% of adults drink excessively, while 26.8% do in Appleton, according to the report.

The La Crosse area has 6.9 bars for every 10,000 people. It's also one of only six U.S. cities where more than one-quarter of adults drink excessively. Eau Claire has the second highest concentration of bars in the nation.

Nearly half of the driving deaths in Green Bay involved alcohol.

For more information on alcohol consumption in Wisconsin and how the state is reacting, visit TMJ4's Project: Drive Sober web page.