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Milwaukee Bucks great Kareem Abdul-Jabbar is special guest at Biden's inauguration

Willy Sanjuan/Willy Sanjuan/Invision/AP

FILE - Kareem Abdul-Jabbar arrives at the ESPY Awards in Los Angeles, in this July 18, 2018, file photo. Abdul-Jabbar revealed he had prostate cancer in a magazine article he wrote about health risks faced by Blacks. Abdul-Jabbar, the NBA's career scoring leader, provided no other details about that illness in the piece he wrote for WebMD that first appeared Wednesday, Dec. 9, 2020. A publicist for Abdul-Jabbar said this is the first time he has spoken about the prostate cancer. (Photo by Willy Sanjuan/Invision/AP, File)

By: Jackson Danbeck

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MILWAUKEE — Milwaukee Bucks great Kareem Abdul-Jabbar is one of a number of people attending Joe Biden's inauguration on Wednesday.

According to a statement from the Presidential Inaugural Committee on Tuesday, Abdul-Jabbar - "the NBA's all-time leading scorer" - will appear during the ceremony. He will be joined by others including Kerry Washington and Eva Longoria, Chef Jose Andres, labor leader Dolores Huerta and the first woman MLB general manager, Kim Ng.

Music will also be a big part of the ceremony, including acts from Kerry Perry, Tyler Hubbard, Tim McGraw, Jon Bon Jovi, the Foo Fighters, Bruce Springsteen and Justin Timberlake.

Abdul-Jabbar was drafted by the one-season-old Bucks in 1969, and spent six seasons in Brew City. He led the Bucks to the team's first NBA Championship in 1771, before being traded to the LA Lakers in 1975.

At the time of his retirement, Abdul-Jabbar scored 38,387 points, the NBA's all-time record.

Inbox: @BidenInaugural announces even more Hollywood celebrities will participate in the primetime Inauguration Day special. Is this an inauguration or the Golden Globes? pic.twitter.com/44kDi1JfNQ
— Joe St. George (@JoeStGeorge) January 20, 2021